A LCR circuit behaves like a damped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator having damping constant 'b', the correct equivalence will be
A
L↔1b, C↔1m, R↔1k
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B
L↔k, C↔b, R↔m
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C
L↔m, C↔k, R↔b
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D
L↔m, C↔1k, R↔b
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Solution
The correct option is DL↔m, C↔1k, R↔b For damped oscillator by Newton's second law −kx−bv=makx+bv+ma=0kx+bdxdt+md2xdt2=0For LCR circuit by KVL −IR−LdIdt−qc=0⟹IR+LdIdt+qc=0⟹qc+Rdqdt+Ld2qdt2=0By comparing R⟹bc⟹1km⟹L