A lead ball and rubber ball having same mass, strike normally on a smooth vertical wall with the same velocity. The lead ball falls down after striking but the rubber ball bounces back. Then

momentum oflead ball is greater than that of rubber ball

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momentum of rubber ball is greater than that of lead ball

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the rubber ball suffers a greater change in momentum as compared to lead ball

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both the balls suffer an equal change in momentum

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Solution

The correct option is C the rubber ball suffers a greater change in momentum as compared to lead ball

Initial moment of both ball is same = mv
V = velocity and m in mass of both ball.
final momentum of lead = $m \times 0 = 0$
final momentum of rubber ball = $m (- v) = m v$
change in momentum of lead ball = mv - 0 = mv
change in momentum of rubber ball = mv - (-mv) = 2mv
So, option C - correct

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