Given that,
Rise temperature =ΔT
Mass of the bullet =m
Now, the kinetic energy associated with the bullet
K.E=12mv2
K.E=12×0.021×(100)2=105J
Now, according to law of conservation of energy
Change in kinetic energy of bullet = change in internal energy of wood
K.E=msΔT
ΔT=K.Ems=105J21×0.03×4.2=39.68oC
Hence, the rise temperature of bullet is 39.68oC