A lead bullet strikes a steel plate with a velocity of $300 m s^{- 1}$ and completely stopped. If the heat produced is shared equally between the bullet and the target the rise in temperature of the bullet in $^{o} C$ is (Sp. heat of lead 0.1255J/gm $^{o} C$ )

89.3

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49.3

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179.283

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358.4

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Solution

The correct option is C $179.283$
Let the mass of the bullet be 'm'.
Assuming that the entire kinetic energy is converted into heat energy.
Bullet receives half of this heat energy and it's temperature rises.
$0.5 (\frac{1}{2} m v^{2}) = m c Δ T$
So, $0.25 (300^{2}) = 125.5 (Δ T)$ [ $c = 125.5 J / k g . K$ ]
Hence, $Δ T = \frac{22500}{125.5} = 179.283^{o} C$

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A lead bullet strikes a steel plate with a velocity of 300ms−1 and completely stopped. If the heat produced is shared equally between the bullet and the target the rise in temperature of the bullet in oC is (Sp. heat of lead 0.1255J/gmoC)

The correct option is C 179.283Let the mass of the bullet be 'm'.Assuming that the entire kinetic energy is converted into heat energy.Bullet receives half of this heat energy and it's temperature rises.0.5(12mv2)=mcΔTSo, 0.25(3002)=125.5(ΔT) [c=125.5J/kg.K]Hence, ΔT=22500125.5=179.283 oC

A lead bullet strikes a steel plate with a velocity of $300 m s^{- 1}$ and completely stopped. If the heat produced is shared equally between the bullet and the target the rise in temperature of the bullet in $^{o} C$ is (Sp. heat of lead 0.1255J/gm $^{o} C$ )