CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Zeff

A leadII sulp...

Question

A lead(II) sulphide crystal has an $N a C l$ structure. What is the density? The edge length of the unit cell is $500 p m$ $.$ N_{0} = 6.023\times 10^{23} $; a t o m i c m a s s :$ Pb = 207.2, S = 32$.

Open in App

Solution

$Z = 4$ , $a = 500 p m$ , $M_{A} = 239.2$ , $ρ = ?$

$ρ = \frac{Z \times M_{A}}{N_{A} \times a^{3}}$
$ρ = \frac{4 \times 239.2}{6.023 \times 10^{23} \times 125 \times 10^{- 24}} = 12.7 g / c m^{3}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A crystal of lead(II) sulphide has

N a C l

structure. In this crystal the shortest distance between

P b^{+ 2}

S^{2 -}

ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide? Also calculate the unit cell volume.

Q. Lead sulphide has face centered cubic crystal structure. If the edge length of the unit cell of lead sulphide is

495 p m

, calculate the density of the crystal. (atomic weight

P b = 207, S = 32

Q. A crystal of lead (II) sulphide has NaCl structure. In this crystal, the shortest distance between

P b^{+ 2}

S^{2 -}

297

pm. What is the length of the edge of the unit cell in lead sulphide? Also calculate the unit cell volume :

Q. A crystal of lead (II) sulphide has NaCl structure. In this crystal, the shortest distance between

P b^{+ 2}

S^{2 -}

297

pm. If the length of the edge of the unit cell in lead sulphide is

5.94 \times 10^{- x}

cm, then value of

x

Q. A crystal of lead (II) sulphide has NaCl structure. In this crystal the shortest distance between a

P b^{2 +}

S^{2 -}

ion is 300 pm. What is the volume of a unit cell of lead sulphide ?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Zeff

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon