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A leadII sulp...

Question

A lead(II) sulphide crystal has an $N a C l$ structure. What is the density? The edge length of the unit cell is $500 p m$ $.$ N_{0} = 6.023\times 10^{23} $; a t o m i c m a s s :$ Pb = 207.2, S = 32$.

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Solution

$Z = 4$ , $a = 500 p m$ , $M_{A} = 239.2$ , $ρ = ?$

$ρ = \frac{Z \times M_{A}}{N_{A} \times a^{3}}$
$ρ = \frac{4 \times 239.2}{6.023 \times 10^{23} \times 125 \times 10^{- 24}} = 12.7 g / c m^{3}$

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