A lead storage battery containing 5-0 L of 1N H2SO4 solution is operated for 9-65- 105 s with a steady current of 100 mA- Assuming volume of the solution remaining constant- normality of H2SO4 will-

The correct option is A remain unchanged Total #160; charge=9.65× 10^5 × 100 × 10^ 3 #160; #160; #160; #160; #160; #160; #160; #160; #1 ...

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Byju's Answer

Standard VII

Chemistry

Faraday's Second Law

A lead storag...

Question

A lead storage battery containing 5.0 L of (1N) $H_{2} S O_{4}$ solution is operated for $9.65 \times 10^{5}$ s with a steady current of 100 mA. Assuming volume of the solution remaining constant, normality of $H_{2} S O_{4}$ will:

remain unchanged

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increases by 0.20

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increase by unity

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decrease by 0.40

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Solution

The correct option is A remain unchanged
$Total charge = 9.65 \times 10^{5} \times 100 \times 10^{- 3}$
$= 9.65 \times 10^{4}$
$= 96500 C$
$= 1 F$
$∴ moles of e^{-} = 1$ as 1 F is charge of 1 mole electrode
But for a lead storage battery,
$H_{2} S O_{4}$ acts just as catalyst
and its concentration does not change during reaction

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Similar questions

A lead storage battery containing 5.0L of $H_{2} S O_{4}$ solution is operated for $9.65 \times 10^{5} s$ with a steady current of 100 mA. Assuming volume of the solution remains constant, normality of $H_{2} S O_{4}$ will :

Q. Fully charged lead storage battery contains

1.5 L

5 M H_{2} S O_{4}

. If

2.5 a m p

of current is taken from the cell for

965

minutes, then what will be the molarity of remaining

H_{2} S O_{4}

? Assume that volume of battery fluid to be constant.

Q. A storage battery contains a solution of

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30% by weight. Find out Molarity?
(Given density of solution

= 1.2 g / c m^{3}

)

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A lead storage battery containing 5.0 L of (1N) H2SO4 solution is operated for 9.65×105 s with a steady current of 100 mA. Assuming volume of the solution remaining constant, normality of H2SO4 will:

The correct option is A remain unchangedTotal charge=9.65×105×100×10−3 =9.65×104 =96500C =1F∴ moles ofe−=1 as 1 F is charge of 1 mole electrodeBut for a lead storage battery,H2SO4 acts just as catalystand its concentration does not change during reaction

A lead storage battery containing 5.0 L of (1N) $H_{2} S O_{4}$ solution is operated for $9.65 \times 10^{5}$ s with a steady current of 100 mA. Assuming volume of the solution remaining constant, normality of $H_{2} S O_{4}$ will: