A leak in the bottom of a tank can empty the full tank in $8$ hour. An inlet pipe fills water at the rate of $6$ liters a minutes. When the tank is full the inlet is opened and due to leak the tank is empty in $12$ hours. How many liters does the cistern hold ?

7580

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7960

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8290

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8640

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Solution

The correct option is D $8640$
Work done by inlet in one hour $= \frac{1}{8} -$ $\frac{1}{12}$
Then, work done by inlet in one minute $= \frac{1}{8} \times \frac{1}{60} = \frac{1}{1440}$
Given volume $= \frac{1}{1440} = 6$ liters
Or whole volume $= 6 \times 1440 = 8640$ liters

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A tank has an inlet pipe and an outlet pipe. If the outlet pipe is closed then the inlet pipe fills the empty tank in 8 hours. If the outlet pipe is open then the inlet pipe fills the empty tank in 10 hours. If only outlet pipe is open then in how many hours the full tank becomes half-full?

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A leak in the bottom of a tank can empty the full tank in 8 hour. An inlet pipe fills water at the rate of 6 liters a minutes. When the tank is full the inlet is opened and due to leak the tank is empty in 12 hours. How many liters does the cistern hold ?

The correct option is D 8640Work done by inlet in one hour =18−112Then, work done by inlet in one minute =18×160=11440Given volume =11440=6 litersOr whole volume=6×1440=8640 liters

A leak in the bottom of a tank can empty the full tank in $8$ hour. An inlet pipe fills water at the rate of $6$ liters a minutes. When the tank is full the inlet is opened and due to leak the tank is empty in $12$ hours. How many liters does the cistern hold ?

The correct option is D $8640$
Work done by inlet in one hour $= \frac{1}{8} -$ $\frac{1}{12}$
Then, work done by inlet in one minute $= \frac{1}{8} \times \frac{1}{60} = \frac{1}{1440}$
Given volume $= \frac{1}{1440} = 6$ liters
Or whole volume $= 6 \times 1440 = 8640$ liters