$A - (B \cup C \cup D) = (A - B) \cap . . . . . . . . \cap . . . . . . . .$

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Solution

Ans. $(A - C) \cap (A - D)$
$L . H . S . = {(B \cup C \cup D)}^{'}$ w.r.t $^{'} A^{'}$
$= B^{'} \cap C^{'} \cap D^{'}$ w.r.t $A$ etc.
$= (A - B) \cap (A - C) \cap (A - D)$

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