A- - 1 3 1 4 - and Aadj A-KI- then the value of -k- is

Generally in Matrices A^ 1=Adj(A)DetA AA^ 1=I AAdj(A)Det(A)=I A(Adj(A))=Det(A)I Comparing it #160; with Question k=Det(A) k=4 3=1 ...

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Scalar Multiplication of a Matrix

a= [ 1 3 1...

Question

a= $[\begin{matrix} 13 \end{matrix} \begin{matrix} 14 \end{matrix}]$ and A(adj A)=KI, then the value of 'k' is

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A = [\begin{matrix} 1 & 2 3 & 4 \end{matrix}]

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A (adj A) = ⎛ ⎜ ⎝ \begin{matrix} 4 & 0 & 0 0 & 4 & 0 0 & 0 & 4 \end{matrix} ⎞ ⎟ ⎠,

det(adj A)

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A (a d j A) = ⎡ ⎢ ⎣ \begin{matrix} 4 & 0 & 0 0 & 4 & 0 0 & 0 & 4 \end{matrix} ⎤ ⎥ ⎦ .

\frac{| a d j (a d j A) |}{| a d j A |}

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