Question

$A_{\left(g\right)}+B_{\left(s\right)}\to {2C}_{\left(g\right)}$, $\Delta H$ and $\Delta S$ respectively are 50 kJ and 100 J/K respectively. Then, at ${227}^{0}C$:

• A. $\Delta G=0$
• B. $\Delta G>0$
• C. $\Delta G=2$
• D. $\Delta G<0$

Answer 1

The correct option is A $\Delta G=0$

$\begin{array}{c}{A}_{\left(g\right)}+B_{\left(s\right)}\to 2C_{\left(g\right)}\\ △H=50kJ=50,000J\\ △S=100J/K\\ T={227}^{0}C=500K\end{array}$

The change in GIbbs free energy is calculated wing the change in enthalpy.

$\begin{array}{c}△G=\Delta H-T.\Delta S\\ △G=50000-500\times 100=0\\ \end{array}$

Option $A$ is correct answer.