A - x - x- N and 3 - x- 6 and B - x - x- N and x - 4- Find A - B-

Given A = ${x : x \in N a n d 3 < x \leq 6}$ and B = ${x : x \in W a n d x < 4}$ . Find : (i) Sets A and B in roster form (ii) $A \cup B$ (iii) $A \cap B$ (iv) A - B (v) B - A

Q. Find

A \cup B

and

A \cap B

for the following sets.
(i)

A = {0, 1, 2, 4, 6}

and

B = {- 3, - 1, 0, 2, 4, 5}

(ii)

A = {2, 4, 6, 8}

and

B = \emptyset

(iii)

A = {x : x \in N, x \leq 5}

and

B =

{

x : x

is a prime number less than 11}
(iv)

A = {x : x \in N, 2 < x \leq 7}

and

B = {x : x \in W, 0 \leq x \leq 6}

Q. Express set

A = {x : x \in N a n d x = 2 n f o r n \in N}

in roster form

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A={x:x∈N and 3<x≤6} and B={x:x∈N and x<4}. Find A−B.

The correct option is A {4,5,6}Given A={x:x∈N and 3<x≤6} and B={x:x∈N and x<4}Given set can be written as,A={4,5,6} and B={1,2,3}∴A−B= the elements which are in set A but not in set B ={4,5,6}Hence, option B is correct.

$A = {x : x \in N a n d 3 < x \leq 6}$ and $B = {x : x \in N a n d x < 4}$ . Find $A - B$ .

The correct option is A ${4, 5, 6}$
Given $A = {x : x \in N and 3 < x \leq 6}$ and $B = {x : x \in N and x < 4}$
Given set can be written as,
$A = {4, 5, 6}$ and $B = {1, 2, 3}$
$∴ A - B =$ the elements which are in set $A$ but not in set $B$ $= {4, 5, 6}$
Hence, option B is correct.