Focal length = f = 20 cm
object distance = - u
image distance = v
magnification = m = -10 [- sign is used because the image is real since it is obtained on screen]
we know, m=v/-u
-10 = v / -u
10 u = v
using,
1/f = 1/v - 1/-u
1/20 = 1/10u + 1/u
1/20 = 1+10 / 10u
10 u / 20 = 11
u = 22 cm
therefore, the object distance is 22 cm
now v=10x22 = 220 cm