A lent Rs. 600 to B for 2 years, and Rs. 150 to C for 4
years and received altogether from both Rs. 90
as interest. Find the rate of interest, simple interest being calculated.

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Solution

Let rate = R% per annum.
Then, [(600 x R x 2)/ 100 ] + [(150 x R x 4 ) / 100] = 90
⇒ 18R = 90
∴ R = 5%
To find time
SInce I = PTR/100
Therefore t = 100I/Pr

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A lent Rs. 600 to B for 2 years, and Rs. 150 to C for 4years and received altogether from both Rs. 90as interest. Find the rate of interest, simple interest being calculated.

Let rate = R% per annum. Then, [(600 x R x 2)/ 100 ] + [(150 x R x 4 ) / 100] = 90⇒ 18R = 90∴ R = 5% To find timeSInce I = PTR/100 Therefore t = 100I/Pr

A lent Rs. 600 to B for 2 years, and Rs. 150 to C for 4
years and received altogether from both Rs. 90
as interest. Find the rate of interest, simple interest being calculated.

Let rate = R% per annum.
Then, [(600 x R x 2)/ 100 ] + [(150 x R x 4 ) / 100] = 90
⇒ 18R = 90
∴ R = 5%
To find time
SInce I = PTR/100
Therefore t = 100I/Pr