A letter is chosen at random from letters of the word $" A S S A S S I N A T I O N "$ . Find the probability of the letter chosen is a vowel.

\frac{1}{4}

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\frac{2}{12}

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\frac{1}{12}

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\frac{6}{13}

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Solution

The correct option is C $\frac{6}{13}$
Given the word $" A S S A S S I N A T I O N "$
Total number of letters $= 13$
Total number of vowels in the word $= 3 (A) + 2 (I) + 1 (O) = 6$
The probability that letter is a vowel, $\frac{n (E)}{n (S)} = \frac{6}{13}$

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