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Combination

A letter lock...

Question

A letter lock consists of $3$ rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most

A

215

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B

243

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C

216

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D

244

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Solution

The correct option is C $215$
Total number of combination of letters of ring $= 6 \times 6 \times 6 = 216$
But among these 1 would be successful event
Therefore total number of unsuccessful events $= 216 - 1 = 215$

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