A letter lock consists of three rings marked with 15 different letters. If N denotes the number of ways in which it is possible to make unsuccessful attempts to open the lock, then
A
48 divides N
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B
N is the product of 3 distinct prime numbers
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C
N is the product of 4 distinct prime numbers
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D
None of these
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Solution
The correct option is BN is the product of 3 distinct prime numbers The total number of possible permutations=15×15×15=3375
and out of all these permutations only one pattern will be the correct one.
Hence total number of unsuccessful attempts =3375−1=3374=2×7×241