Question

Question 33
A letter of English alphabets is chosen at random. Determine the probability that the letter is a constant.

Answer 1

We know that, in english alphabets, there are (5 vowels + 21 consonants) = 26 letters. So, total number of outcomes in english alphabets are,
n(S) = 26
Let E = Event of choosing a english alphabet, which is a consonent
={b,c,d,f,g,h,j,k,l,m,n,p,q,r,s,t,v,w,x,y,z}
$\therefore n\left(E\right)=21$
Hence, required probability $=\frac{n\left(E\right)}{n\left(S\right)}=\frac{21}{26}$