a level flight plane flying at altitude of 1024 ft with speed of 240 ft/s is overtaking a motor boat travelling at 80 ft/s in same direction as plane. at what horizontal distance before boat should a bag be dropped from plane in order to hit boat?

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Solution

$t i m e t a k e n i n t r a v e l l i n g t h e v e r t i c a l d i s \tan c e i s t . 1024 = 0 + \frac{1}{2} g t^{2} t^{2} = 2 \times 1024 \times 10 t = 143.10 s r e l a t i v e v e l o c i t y b e t w e e n t h e b o a t a n d t h e p l a n e = 240 - 80 = 160 f t / s d i s \tan c e d i s g i v e n b y : d = 160 \times 143 . 10 = 22879 f t$

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a level flight plane flying at altitude of 1024 ft with speed of 240 ft/s is overtaking a motor boat travelling at 80 ft/s in same direction as plane. at what horizontal distance before boat should a bag be dropped from plane in order to hit boat?

time taken in travelling the vertical distance is t.1024 = 0+12gt2t2 = 2×1024×10t = 143.10 srelative velocity between the boat and the plane =240-80 = 160ft/sdistance d is given by:d= 160×143. 10=22879 ft