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Question

A license plate begins with three letters. If the possible letters are A,B,C,D,E,F,G and H, how many different permutations of these letters can be made if no letter is used more than once?

A
336
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B
83
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C
3!
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D
8!
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Solution

The correct option is A 336
The problem involves 8 things (A,B,C,D,E,F,G,H) taken 3 at a time.

Required number of permutations
=P(8,3)=8!(83)!=8×7×6×5!5!=8×7×6=336

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