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Byju's Answer

Standard XII

Physics

Applying NLM along 3 Axis

A life can mo...

Question

A life can move upward or downward. A light inextensible string fixed from the ceiling of the lift with a frictionless pulley and tension in string $T_{1}$ . Two masses of $m_{1}$ and $m_{2}$ are connected with inextensible light string and tension in this string $T_{2}$ as shown in the figure. Read the question carefully and answer.
If $m_{1} + m_{2} = m$ and lift is moving with a constant velocity then value of $T_{1}$

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Solution

The correct option is D $=$ mg
$\begin{matrix} correct option is (B) Let us take (m_{1} + m_{2}) as a system: If the lift is moving with a constant velocity so, a net = 0 Hence T_{1} = (m_{1} + m_{2}) g T_{1} = m g \end{matrix}$

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Two bodies of masses m₁ and m₂ are connected by a light, inextensible string, which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

Q. Two particles of masses

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Q. Three blocks of masses

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. Pulleys and string are light. Part of the string connecting both pulleys is vertical and part of the string connecting pulleys with masses

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are horizontal.

(P) Acceleration of mass $M_{1}$	(1) $\frac{F}{M_{2}}$
(Q) Acceleration of mass $M_{2}$	(2) $\frac{F}{M_{1} + M_{2}}$
(R) Acceleration of mass $M$	(3) zero
(S) Tension in the string	(4) $\frac{M_{2} F}{M_{1} + M_{2}}$

Three blocks of mass $M_{1}$ , $M_{2}$ & $M_{3}$ are connected by massless strings as shown on a frictionless table. Where $T_{1}$ is the tension in the string between block $M_{1}$ and $M_{2}$ , $T_{2}$ is the tension in the string between block $M_{2}$ and $M_{3}$ . They're pulled with a force $F = 40 N$ . If $M_{1}$ =10 kg, $M_{2}$ = 6 kg and $M_{3}$ = 4 kg, then tension $T_{2}$ will be:

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The correct option is D =mg correct option is (B) Let us take (m1+m2) as a system: If the lift is moving with a constant velocity so, a net =0 Hence T1=(m1+m2)gT1=mg

The correct option is D $=$ mg
$\begin{matrix} correct option is (B) Let us take (m_{1} + m_{2}) as a system: If the lift is moving with a constant velocity so, a net = 0 Hence T_{1} = (m_{1} + m_{2}) g T_{1} = m g \end{matrix}$