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Question

A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are only given to persons having age 18 years onwards but less than 60 years.

Age in years
No. of policy holders
Below 20
2
Below 25
6
Below 30
24
Below 35
45
Below 40
78
Below 45
89
Below 50
92
Below 55
98
Below 60
100

A
47.12 years
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B
15.65 years
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C
25.17 years
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D
35.76 years
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Solution

The correct option is D 35.76 years
Class IntervalNo. of policy Holders
Freq (Fi)
XI
18 to 20 2 2
20 to 25 4 6
25 to 30 18 24
30 to 35 21 45
35 to 40 33 78
40 to 45 11 89
45 to 50 3 92
50 to 55 6 98
55 to 60 2 100
N=100
For continuous data, median
=L+(N2Cf)×H
Where N = Total cumulative frequency
L = lower limit of the median class Interval;
Median Class = the class interval having cumulative
freqN2
C= cumulative frequency of the class interval just before the median class interval
f= frequency of the median class interval;
H= width of the median class interval
Here N=100N2=50
this cumulative freq lies within interval (3540);L=35;C=45;f=33;H=5
Hence median =35+⎜ ⎜ ⎜10024533×5⎟ ⎟ ⎟=35+(504533×5)=35+(2533)=35+0.7575=35+.76=35.76

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