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Question

A lift is falling with an acceleration \(2~m/s^2\). A ball of mass \(100~gm\) is attached at one end of the string and the other end is fixed to the ceiling of the lift. The ball remains at rest relative to lift. The tension (in \(N\)) in the string is: \((g=10~ m/s^2\) )

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Solution

Acceleration of lift downward = \(2~m/s^2\)
Mass of the ball \(100~gm\)
Tension in the string is given by,
\(T = ma(g-a\))
\(=0.1(10-2)\)
\(=0.8~N\)

Final answer: 0.8


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