Question

A lift is going up. The variation in the speed of the lift is as given in the graph. What is height to which the lift takes the passenger:

• A. 3.6 m
• B. 28.8 m
• C. 36.0 m
• D. Cannot be calculated from the above graph

Answer 1

The correct option is C 36.0 m

We know that area under velocity-time graph gives us total displacement.

Here the displacement is the vertical height, that he lift caries the passengers.

So area of the graph = $(\frac{1}{2}\times 2\times 3.6)+(8\times 3.6)+(\frac{1}{2}\times 2\times 3.6)$

A= $7.2+28.8=36$

Hence the height is $36.0m$