A lift is moving down with a retardation of $5 m s^{- 2}$ . Calculate the percentage change in the weight of the person in the lift ( $g = 10 m s^{- 2}$ ).

25%

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50%

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75%

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60%

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Solution

The correct option is B 50%
The acceleration of lift when it moving down $a = g - A = 10 - 5 = 5 m / s^{2}$
The % change $δ A = \frac{g - A}{g} * 100 = \frac{5}{10} * 100 = 50 %$

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A lift is moving down with a retardation of 5ms−2. Calculate the percentage change in the weight of the person in the lift (g=10ms−2).

The correct option is B 50%The acceleration of lift when it moving down a=g−A=10−5=5m/s2The % change δA=g−Ag∗100=510∗100=50%

A lift is moving down with a retardation of $5 m s^{- 2}$ . Calculate the percentage change in the weight of the person in the lift ( $g = 10 m s^{- 2}$ ).

The correct option is B 50%
The acceleration of lift when it moving down $a = g - A = 10 - 5 = 5 m / s^{2}$
The % change $δ A = \frac{g - A}{g} * 100 = \frac{5}{10} * 100 = 50 %$