A lift is moving down with an acceleration a. A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground respectively are :

a, g

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(g – a), g

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a, a

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g, g

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Solution

The correct option is B
(g – a), g

\(a_{bl]=a_b-a_l=(g-a)\downarrow~~~~~~a_b=g\downarrow\)

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