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Second Law of Motion

A lift is mov...

Question

A lift is moving down with the acceleration 3 m/s². A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.

A

1.7 s

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B

0.5 s

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C

0.71 s

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D

7.1 s

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Solution

The correct option is C
0.71 s

Relative acceleration is,

a = 9.8 - 3 = 6.8 m/s²

Now, we have

S = ut + (1/2)at²

Here, u = 0 and S = 1.7 m

Therefore, t = 0.71 s

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