A lift is moving downwards with an acceleration equal to acceleration due to gravity. A body of mass $M$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $μ$ , then the frictional resistance offered by the body is:

M g

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μ

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2 μ

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Zero

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Solution

The correct option is D Zero
( $N$ = normal, $m$ = mass of object, $a$ = acceleration of lift)
$m g - N = m a$
$N = m a - m g$
(given $a = g$ )
therefore
$N = 0$
friction $= u . N$
hence friction $= u .0$ (N=0)
$= 0$

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A lift is moving downwards with an acceleration equal to acceleration due to gravity. A body of mass M kept on the floor of the lift is pulled horizontally. If the coefficient of friction is μ, then the frictional resistance offered by the body is:

The correct option is D Zero(N = normal, m = mass of object, a = acceleration of lift)mg−N=ma N=ma−mg(given a=g) therefore N=0friction =u.N hence friction =u.0 (N=0) =0

A lift is moving downwards with an acceleration equal to acceleration due to gravity. A body of mass $M$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $μ$ , then the frictional resistance offered by the body is:

The correct option is D Zero
( $N$ = normal, $m$ = mass of object, $a$ = acceleration of lift)
$m g - N = m a$
$N = m a - m g$
(given $a = g$ )
therefore
$N = 0$
friction $= u . N$
hence friction $= u .0$ (N=0)
$= 0$