A lift is moving up with acceleration a. A person inside the lift throws the ball upwards with a velocity u relative to hand. What is the time of flight of the ball?
A
2u(g+a)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
u(g+a)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
u2(g+a)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2u(g−a)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2u(g+a) Acceleration of ball w.r.t lift =a+g
¯s=¯ut+12¯aBLt2 0=uT−12(g+a)T2 Therefore, the time of flight of the ballT=2u(g+a).