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Standard XII

Physics

Pure Rotation about an Axis

A lift is mov...

Question

A lift is moving upwards with a uniform velocity $v$ in which a block of mass $m$ is lying. The frictional force offered by the block, when coefficient of friction is $μ$ will be :-

zero

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m g

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μ m g

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2 μ m g

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Solution

The correct option is A zero
There is no force parallel to the plane of interaction of block and plane.
Because no frictional force
f=0

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A lift is moving upwards with a uniform velocity v in which a block of mass m is lying. The frictional force offered by the block, when coefficient of friction is μ will be :-

The correct option is A zeroThere is no force parallel to the plane of interaction of block and plane.Because no frictional forcef=0

A lift is moving upwards with a uniform velocity $v$ in which a block of mass $m$ is lying. The frictional force offered by the block, when coefficient of friction is $μ$ will be :-

The correct option is A zero
There is no force parallel to the plane of interaction of block and plane.
Because no frictional force
f=0