The correct option is B 64 m
From 0−4 s the motion is with constant acceleration, the distance can be calculated from kinematics equation
S0−4=0+122×42=16 m
From 4−8 s the motion is with constant velocity,
v=u+at=0+2×4=8 m/s
S4−8=v×t=8×4=32 m
From 8−12 s the motion is with constant acceleration, the distance can be calculated from kinematics equation
S8−12=8×4−122×42=16 m
Total distance covered =16+32+16 m=64 m