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Question

A lift starts from rest. Its acceleration is plotted against time. When it comes to rest the total distance travelled is

A
20 m
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B
64 m
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C
32 m
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D
36 m
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Solution

The correct option is B 64 m
From 04 s the motion is with constant acceleration, the distance can be calculated from kinematics equation
S04=0+122×42=16 m
From 48 s the motion is with constant velocity,
v=u+at=0+2×4=8 m/s
S48=v×t=8×4=32 m
From 812 s the motion is with constant acceleration, the distance can be calculated from kinematics equation
S812=8×4122×42=16 m
Total distance covered =16+32+16 m=64 m

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