A lift whose cage is 3 m high is moving up with an acceleration of 2 m/s2. A piece of stone is dropped from the top of the cage of the lift when its velocity is 8 m/s. If g=10 m/s2, then the stone will reach the floor of the lift after.
The time taken to reach the stone on the floor is given as,
s=ut+12(a+g)t2
3=8×t+12(2+10)t2
3=8×t+6t2
t=0.3052sec