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Kirchhoff's Junction Law

A light bulb ...

Question

A light bulb is rated at $100$ W for a $220$ V supply. Find the peak voltage of the source.

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Solution

The peak voltage of the source for bulb rated $V$ volts is $\sqrt{2} V$
Hence peak voltage $= \sqrt{2} \times 220 V$
$= 311 V$

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