Question

A light has amplitude $A$ (after polariser) and angle between analyser and polariser is ${60}^{\circ }$. Light is reflected by analyser has amplitude

• A. $A\sqrt{2}$
• B. $A/\sqrt{2}$
• C. $\sqrt{3}A/2$
• D. $A/2$

Answer 1

Answer: (D)

$A/2$

$\theta ={60}^0$

$A=acos\theta$

$A_{new}=Acos{60}^0$

$A_{new}=A\times \frac{1}{2}$

$A_{new}=\frac{A}{2}$