Question

A light metal wire of length L is suspended vertically from a rigid support, when a body of mass M is attached to the lower end of wire, the elongation of the wire is $\Delta L$ in its equilibrium position then.

• A. The loss in gravitational potential energy of mass M is $Mg\Delta L$
• B. The elastic potential energy stored in the wire is $Mg\Delta L$
• C. The elastic potential energy stored in the wire is $\frac{1}{2}Mg\Delta L$
• D. None of these

Answer 1

Answer: (A), (C)

The correct options are
A The loss in gravitational potential energy of mass M is $Mg\Delta L$
C The elastic potential energy stored in the wire is $\frac{1}{2}Mg\Delta L$