Light of wavelength λ shines on a metal surface with intensity X, and the metal emits Y electrons per second of average energy Z. What will happen to Y and Z If X is doubled?
Y will be doubled but Z will remain same.
When know that,
In photoelectric effect:
→ The number of electrons ejected are proportional to intensity of light
→ Intensity does not affect average energy of photo-electrons.
Now, when intensity is doubled
Number of electrons emitted per second will be doubled. (y) No effect on average energy of photo-electrons. (z)
⇒ Y → Doubled
Z → Same