A light of wavelength $λ$ strikes a metal surface with intensity X and the metal emits Y electrons per second of average energy Z. What will happen to Y and Z if X is halved?

Y will be halved

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Y will double

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Y will be remain same

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Z will be halved

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Solution

The correct option is A Y will be halved
The number of emitted electrons is directly proportional to the intensity of incident light. Therefore, as X is halved Y will also be halved.
Above the threshold frequency, the maximum kinetic energy of the emitted electrons is independent of the intensity of the incident light and depends only on the frequency (or wavelength) of the incident light. So Z will remain the same.

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