A light ray is incident along normal of AB as shown below- If the critical angle is 60- the angle of the refracted ray is-A- 60-B- 90-C- 30-

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Standard X

Physics

Lateral Displacement

A light ray i...

Question

A light ray is incident along normal of AB as shown below. If the critical angle is $60^{\circ}$ , the angle of the refracted ray is .

60^{\circ}

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90^{\circ}

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30^{\circ}

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Solution

The correct option is B $90^{\circ}$
The incident ray on the surface $A B$ passes through the normal without any refraction.
Given, critical angle = $60^{\circ}$
At point $E$ the angle of incidence can be calculated as
$150^{\circ}$ - $90^{\circ}$ = $60^{\circ}$ ,
Therefore the angle of the refracted ray would be $90^{\circ}$ .

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A light ray is incident along normal of AB as shown below. If the critical angle is 60∘, the angle of the refracted ray is .

The correct option is B 90∘The incident ray on the surface AB passes through the normal without any refraction. Given, critical angle = 60∘ At point E the angle of incidence can be calculated as 150∘ - 90∘ = 60∘, Therefore the angle of the refracted ray would be 90∘.

A light ray is incident along normal of AB as shown below. If the critical angle is $60^{\circ}$ , the angle of the refracted ray is .