A light ray is incident, at an incident angle $θ_{1}$ , on the system of two plane mirrors $M_{1} and M_{2}$ having an incilination angle $75^{\circ}$ between them(as shown in figure). After reflecting from mirror $M_{1}$ it gets reflected back by the mirror $M_{2}$ with an angle of reflection $30^{\circ}$ . The total deviation of the ray will bedegree.

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Solution

On first reflection angle of deviation is $90^{\circ}$ and on second reflection angle of deviation is $120^{\circ}$
So total deviation is

$δ = 90^{\circ} + 120^{\circ} = 210^{\circ}$ .

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On first reflection angle of deviation is 90∘ and on second reflection angle of deviation is 120∘ So total deviation is δ=90∘+120∘=210∘.

On first reflection angle of deviation is $90^{\circ}$ and on second reflection angle of deviation is $120^{\circ}$
So total deviation is

$δ = 90^{\circ} + 120^{\circ} = 210^{\circ}$ .