A light ray is incident on air-liquid interface at 45∘ and is refracted at 30∘. What is the refractive index of the liquid?

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Solution

Given:
The angle of incidence,
i = 45 $°$
The angle of refraction,
r = 30 $°$
The refractive index is,

Consider the formula
n = $\frac{sin i}{sin r}$
● Substitute the values
n = $\frac{sin 45 °}{sin 30 °}$

Continue the further calculation
n = $\frac{sin \frac{1}{\sqrt{2}}}{sin \frac{1}{2}}$
n = $\frac{2}{\sqrt{2}}$
n = $\sqrt{2}$

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A light ray is incident on air-liquid interface at 45∘ and is refracted at 30∘. What is the refractive index of the liquid?

Given: The angle of incidence, i = 45° The angle of refraction, r = 30° The refractive index is, Consider the formula n = sinisinr﻿ ● Substitute the values n = sin45°sin30° Continue the further calculation n = sin1√2sin12 n = 2√2 n = √2