A light ray is incident on transparent sphere of $refractive index=2$ , at angle $i = 45^{0}$ . What is the deviation (in degrees) of a tiny fraction of the ray which enters the sphere, undergoes two total internal reflection and then refracts out into air?

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Solution

We know that : $n_{1} s i n i = n_{2} s i n r$
According to ray diagram

$\Rightarrow 1 s i n 45^{0} = \sqrt{2} s i n r \Rightarrow r = 30^{0}$
$δ = 360^{0} - 90^{0} = 270^{0}$

$δ = 270^{0}$

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Refractive Index

Standard X Physics

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A light ray is incident on transparent sphere of refractive index=2 , at angle i=450. What is the deviation (in degrees) of a tiny fraction of the ray which enters the sphere, undergoes two total internal reflection and then refracts out into air?

We know that : n1sin i=n2sin r According to ray diagram ⇒1 sin 450=√2sin r⇒r=300 δ=3600−900=2700 δ=2700

A light ray is incident on transparent sphere of $refractive index=2$ , at angle $i = 45^{0}$ . What is the deviation (in degrees) of a tiny fraction of the ray which enters the sphere, undergoes two total internal reflection and then refracts out into air?

We know that : $n_{1} s i n i = n_{2} s i n r$
According to ray diagram

$\Rightarrow 1 s i n 45^{0} = \sqrt{2} s i n r \Rightarrow r = 30^{0}$
$δ = 360^{0} - 90^{0} = 270^{0}$

$δ = 270^{0}$