A light ray passes from air through a thin rectangular plastic slab (refractive index = 1.3). If the ray in air makes an angle of 45∘ with the normal after leaving the slab, what is the angle of incidence for the light falling on the plastic slab?
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Solution
For a rectangular slab, there is no change in the direction of the emergent ray. It is only shifted a little sideways. So the angle of incidence is equal to the angle of emergence, i.e., 45∘.