A light ray passes from water to air. How does the speed of light change?

decreases

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remains same

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increases

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none of these

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Solution

The correct option is C increases
We know , $V_{a i r} μ_{a i r} = V_{w a t e r} μ_{w a t e r}$
We know, $μ_{a i r} = 1, μ_{w a t e r} = 4 / 3$
$V_{a i r} = \frac{4}{3} V_{w a t e r}$
Hence, velocity will increase.

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A light ray passes from water to air. How does the speed of light change?

The correct option is C increasesWe know ,Vairμair=Vwaterμwater We know, μair=1, μwater=4/3Vair=43VwaterHence, velocity will increase.

The correct option is C increases
We know , $V_{a i r} μ_{a i r} = V_{w a t e r} μ_{w a t e r}$
We know, $μ_{a i r} = 1, μ_{w a t e r} = 4 / 3$
$V_{a i r} = \frac{4}{3} V_{w a t e r}$
Hence, velocity will increase.