1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A light rod of length l has two masses m1 and m2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

A
m1m2l2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
m1m2m1+m2l2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
m1+m2m1m2l2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
(m1+m2)l2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B m1m2m1+m2l2The distance of center of mass from mass m1 is x1=m2lm1+m2 The distance of center of mass from mass m2 is x2=m1lm1+m2 Hence, moment of inertia of masses about the center of mass =m1x21+m2x22 =m1(m2lm1+m2)2+m2(m1lm1+m2)2 On simplifying above equation we get, =m1m2m1+m2l2

Suggest Corrections
70
Join BYJU'S Learning Program
Related Videos
Moment of Inertia of Solid Bodies
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program