A light source lies at the angle bisector of two plane mirrors inclined at an angle of θ. The limitation for the value of θ so that the light reflected from one mirror does not reach the other mirror will be
A
θ≤120∘
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B
θ≤90∘
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C
θ≥120∘
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D
θ≥60∘
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Solution
The correct option is Cθ≥120∘ For the symmetric placement (object lies at angle bisector), the number of images formed will be N=n−1=360∘θ−1, irrespective of 360∘θ being even or odd. For no successive reflection to occur, number of image formed will be 2 (1 each from individual mirror) N≤2 ⇒n−1≤2 ⇒n≤3 ⇒360∘θ≤3 ⇒θ≥120∘