Question

A light string passes over a frictionless pulley. To one of its ends a mass of $6kg$ is attached and to its other end a mass of $10kg$ is attached. The tension in the string will be:

• A. $50N$
• B. $75N$
• C. $100N$
• D. $150N$

Answer 1

Answer: (B)

$75N$

Let tension in the string be $T$ and acceleration of the system be $a$

so for mass, $10kg$ for equation can be written as:

$10g-T=10a$

And for mass $6kg$

$T-6g=6a$

equating above equation

$\frac{10g-T}{10}=\frac{T-6g}{6}$

$T=\frac{120g}{16}=75N$