A light wave enters from air into a medium of refractive index 43. If wavelength of light in air is 6000˚A, then the wave number of light in the medium is:
A
1.1×106
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B
2.2×106
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C
4.4×106
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D
6×106
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Solution
The correct option is B2.2×106 Wave number is reciprocal of wavelength. Wave number is given by ¯v=1λ′=μλ (As, λ′=λμ) ⇒¯v=436000×10−10 =4×1073×6=2.2×106/m