Question

A line AB is of length 6 cm. Another line CD is of length 15 cm. What fraction is:
ii) $\frac{1}{2}$ the length of AB to that of $\frac{1}{3}$ of CD?

Answer 1

Step: Finding the required fraction
We have,
Length of AB = 6 cm.
Length of CD = 15 cm.
Now A. T.Q

$\frac{1}{2}$ Length of AB =$\frac{1}{2}\times 6=3cm$

And,

$\frac{1}{3}$ Length of CD =$\frac{1}{2}\times 15=5cm$

Required fraction $\frac{\frac{1}{2}oflengthofAB}{\frac{2}{3}ofLengthofCD}$

=$\frac{3cm}{5cm}=\frac{3}{5}$
Hence, the fraction of the $\frac{1}{2}$ length of AB to that $\frac{1}{3}$ length of CD is $\frac{3}{5}$