Question

A line AB is of length 6 cm. Another line CD is of length 15 cm . What fracation is:
iii $\frac{1}{2}$ of CD to that of AB?

Answer 1

Step: Finding the required fraction
We have,
Length of AB = 6 cm.
Length of CD = 15 cm.
Now,
$\frac{1}{5}$Length of CD =$\frac{1}{5}\times 15=3cm$
Required fraction =$\frac{\frac{1}{2}oflengthofCD}{lengthofAB}$

=$\frac{3cm}{6cm}=\frac{1}{2}$

Hence, the fractions of the $\frac{1}{5}$ length of CD to that of AB is $\frac{1}{2}$.