Question

A line drawn through the mid-point of one side of a triangle is parallel to another side, so it divides the third side in the ratio:

• A. $1:1$
• B. $2:1$
• C. $1:2$
• D. $3:1$

Answer 1

The correct option is C $1:2$

In $△ABC$, D is the midpoint of side BC and line ED is drawn to intersect side AB such that $A-E-B$.

Also, side $ED\parallel$ side $AC$.

$\frac{BD}{BC}=\frac{BE}{BA}$ ...By B.P.T.

$\Rightarrow \frac{1}{2}=\frac{BE}{BA}$

$\Rightarrow E$ is the mid point of $AB$