A line drawn through the point P (-1, 2) meets the hyperbola xy=c2 at the points A and B (points A and B lie on same side of P) . Q is a point on AB such that PA, PQ and PB are in H.P then locus of Q is
A
x−2y=2c2
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B
2x−y=2c2
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C
2x+y+2c2=0
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D
x+2y+2c2
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Solution
The correct option is B2x−y=2c2 Locus of Q is S1=0 2x−y=2c2